What is the answer to 4^{2x+1}=3^{x+5} ?

The answer to 4^{2x+1}=3^{x+5} is x=(5ln(3)-2ln(2))/(4ln(2)-ln(3))

Solve for x: 4^{2x+1}=3^{x+5}

The solution is x=(5ln(3)-2ln(2))/(4ln(2)-ln(3))

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4^{2 x + 1} = 3^{x + 5}

x = \frac{5 ln ( 3 ) - 2 ln ( 2 )}{4 ln ( 2 ) - ln ( 3 )}

Decimal Notation

x = 2.45330 \dots

Solution steps

4^{2 x + 1} = 3^{x + 5}

Apply exponent rules

(2 x + 1) ln (4) = (x + 5) ln (3)

Solve

(2 x + 1) ln (4) = (x + 5) ln (3) : x = \frac{5 ln ( 3 ) - 2 ln ( 2 )}{4 ln ( 2 ) - ln ( 3 )}

x = \frac{5 ln ( 3 ) - 2 ln ( 2 )}{4 ln ( 2 ) - ln ( 3 )}

3^{x + 3} = \frac{1}{81}

3 \times 9^{x} = 81

3^{5 x^{2}} = 9^{x}

y, e^{- x^{2} - y^{2}} = 0

(e^{4})^{x} + 4 (e^{2})^{x} - 21 = 0

What is the answer to 4^{2x+1}=3^{x+5} ?
The answer to 4^{2x+1}=3^{x+5} is x=(5ln(3)-2ln(2))/(4ln(2)-ln(3))
Solve for x: 4^{2x+1}=3^{x+5}
The solution is x=(5ln(3)-2ln(2))/(4ln(2)-ln(3))