What is the answer to 9^{1-x}=16 ?

The answer to 9^{1-x}=16 is x=-(2ln(2)-ln(3))/(ln(3))

Solve for x: 9^{1-x}=16

The solution is x=-(2ln(2)-ln(3))/(ln(3))

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9^{1 - x} = 16

x = - \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 3 )}

Decimal Notation

x = - 0.26185 \dots

Solution steps

9^{1 - x} = 16

Apply exponent rules

(1 - x) ln (9) = ln (16)

Solve

(1 - x) ln (9) = ln (16) : x = - \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 3 )}

x = - \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 3 )}

3 e^{x} = 12

e^{1 - 4 x} = 3

e^{1 - 4 x} = 7

3^{x} \cdot 5^{x} = 3.375

3^{2 x - 4} = 9

What is the answer to 9^{1-x}=16 ?
The answer to 9^{1-x}=16 is x=-(2ln(2)-ln(3))/(ln(3))
Solve for x: 9^{1-x}=16
The solution is x=-(2ln(2)-ln(3))/(ln(3))