What is the answer to 9^{x-2}=27^{1-x} ?

The answer to 9^{x-2}=27^{1-x} is x= 7/5

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9^{x-2}=27^{1-x}

9^{x - 2} = 2 7^{1 - x}

x = \frac{7}{5}

Decimal Notation

x = 1.4

Solution steps

9^{x - 2} = 2 7^{1 - x}

Apply exponent rules

2 (x - 2) = 3 (1 - x)

Solve

2 (x - 2) = 3 (1 - x) : x = \frac{7}{5}

x = \frac{7}{5}

- e^{- x} + 2 e^{2 x} = 0

z, z = 3^{m}

\frac{6}{5 ^{- 7 x + 2}} = \frac{3}{3 ^{- 12 x + 5}}

e^{x + 7} = 5

10 0^{x + 5} = 1 0^{x^{2} - x + 12}

What is the answer to 9^{x-2}=27^{1-x} ?
The answer to 9^{x-2}=27^{1-x} is x= 7/5
Solve for x: 9^{x-2}=27^{1-x}
The solution is x= 7/5