What is the answer to 7^{3x+1}=5^x ?

The answer to 7^{3x+1}=5^x is x=-(ln(7))/(3ln(7)-ln(5))

Solve for x: 7^{3x+1}=5^x

The solution is x=-(ln(7))/(3ln(7)-ln(5))

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7^{3 x + 1} = 5^{x}

x = - \frac{ln ( 7 )}{3 ln ( 7 ) - ln ( 5 )}

Decimal Notation

x = - 0.46021 \dots

Solution steps

7^{3 x + 1} = 5^{x}

Apply exponent rules

(3 x + 1) ln (7) = x ln (5)

Solve

(3 x + 1) ln (7) = x ln (5) : x = - \frac{ln ( 7 )}{3 ln ( 7 ) - ln ( 5 )}

x = - \frac{ln ( 7 )}{3 ln ( 7 ) - ln ( 5 )}

12 \cdot 2^{x} = 1

4^{x} - 3 \times 2^{x} - 4 = 0

5^{x + 1} = 4^{2 x}

e^{- x} x = 0

6^{x + 1} - 18 \times 6^{x - 1} = 108

What is the answer to 7^{3x+1}=5^x ?
The answer to 7^{3x+1}=5^x is x=-(ln(7))/(3ln(7)-ln(5))
Solve for x: 7^{3x+1}=5^x
The solution is x=-(ln(7))/(3ln(7)-ln(5))