What is the answer to 3^x-2\times 3^{x-2}=7 ?

The answer to 3^x-2\times 3^{x-2}=7 is x=2

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3^x-2\times 3^{x-2}=7

3^{x} - 2 \cdot 3^{x - 2} = 7

x = 2

Solution steps

3^{x} - 2 \cdot 3^{x - 2} = 7

Factor

3^{x} - 2 \cdot 3^{x - 2} : 7 \cdot 3^{x - 2}

7 \cdot 3^{x - 2} = 7

Divide both sides by

7

3^{x - 2} = 1

Apply exponent rules

(x - 2) ln (3) = ln (1)

Solve

(x - 2) ln (3) = ln (1) : x = 2

x = 2

2^{x + 1} + 5 (2^{x}) = 28

2^{2 x - 3} = 128

2^{2 x - 7} = 16

2 = (1.07)^{x}

6^{2 x + 1} = 216

What is the answer to 3^x-2\times 3^{x-2}=7 ?
The answer to 3^x-2\times 3^{x-2}=7 is x=2
Solve for x: 3^x-2\times 3^{x-2}=7
The solution is x=2