What is the answer to 4^{-4x}=25 ?

The answer to 4^{-4x}=25 is x=-(ln(5))/(4ln(2))

Solve for x: 4^{-4x}=25

The solution is x=-(ln(5))/(4ln(2))

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4^{- 4 x} = 25

x = - \frac{ln ( 5 )}{4 ln ( 2 )}

Decimal Notation

x = - 0.58048 \dots

Solution steps

4^{- 4 x} = 25

Apply exponent rules

- 4 x ln (4) = ln (25)

Solve

- 4 x ln (4) = ln (25) : x = - \frac{ln ( 5 )}{4 ln ( 2 )}

x = - \frac{ln ( 5 )}{4 ln ( 2 )}

5^{8} \cdot 5^{4} = (125)^{x}

2^{4 x - 1} = 1

y, x = 1 + y + e^{y}

e^{4 x} = 32

3^{\frac{1}{x}} = 9

What is the answer to 4^{-4x}=25 ?
The answer to 4^{-4x}=25 is x=-(ln(5))/(4ln(2))
Solve for x: 4^{-4x}=25
The solution is x=-(ln(5))/(4ln(2))