What is the answer to (7^{x+3}7^{-7})^2=7 ?

The answer to (7^{x+3}7^{-7})^2=7 is x= 9/2

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(7^{x+3}7^{-7})^2=7

(7^{x + 3} 7^{- 7})^{2} = 7

x = \frac{9}{2}

Decimal Notation

x = 4.5

Solution steps

(7^{x + 3} \cdot 7^{- 7})^{2} = 7

Apply exponent rules

2 (x - 4) = 1

Solve

2 (x - 4) = 1 : x = \frac{9}{2}

x = \frac{9}{2}

x^{9} = e^{x}

e^{- 2 x} = 0.025

e^{1 - 4 x} = 12

(\frac{1}{5})^{2 - 3 x} = 25

e^{8 x + 4} = 11 e^{3 x}

What is the answer to (7^{x+3}7^{-7})^2=7 ?
The answer to (7^{x+3}7^{-7})^2=7 is x= 9/2
Solve for x: (7^{x+3}7^{-7})^2=7
The solution is x= 9/2