What is the answer to 6^{x+2}= 1/(3^x) ?

The answer to 6^{x+2}= 1/(3^x) is x=-(2ln(6))/(ln(18))

Solve for x: 6^{x+2}= 1/(3^x)

The solution is x=-(2ln(6))/(ln(18))

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6^{x + 2} = \frac{1}{3 ^{x}}

x = - \frac{2 ln ( 6 )}{ln ( 18 )}

Decimal Notation

x = - 1.23981 \dots

Solution steps

6^{x + 2} = \frac{1}{3 ^{x}}

Apply exponent rules

(x + 2) ln (6) = - x ln (3)

Solve

(x + 2) ln (6) = - x ln (3) : x = - \frac{2 ln ( 6 )}{ln ( 18 )}

x = - \frac{2 ln ( 6 )}{ln ( 18 )}

Verify Solutions:

x = - \frac{2 ln ( 6 )}{ln ( 18 )}

True

The solution is

x = - \frac{2 ln ( 6 )}{ln ( 18 )}

3^{2 x - 2} + 7 = 4 (3^{x - 1} + 1)

y, 17 y e^{- x^{2} - y^{2}} - 34 x^{2} y e^{- x^{2} - y^{2}} = 0

2^{x + 6} = 2^{5}

9^{x} - 8 \times 3^{x} - 9 = 0

(5^{x - 2})^{x - 3} = 1

What is the answer to 6^{x+2}= 1/(3^x) ?
The answer to 6^{x+2}= 1/(3^x) is x=-(2ln(6))/(ln(18))
Solve for x: 6^{x+2}= 1/(3^x)
The solution is x=-(2ln(6))/(ln(18))