What is the answer to (1/27)^{2x+5}=3 ?

The answer to (1/27)^{2x+5}=3 is x=-8/3

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(1/27)^{2x+5}=3

(\frac{1}{27})^{2 x + 5} = 3

x = - \frac{8}{3}

Decimal Notation

x = - 2.66666 \dots

Solution steps

(\frac{1}{27})^{2 x + 5} = 3

Apply exponent rules

- 3 (2 x + 5) = 1

Solve

- 3 (2 x + 5) = 1 : x = - \frac{8}{3}

x = - \frac{8}{3}

4^{2 x} = 8^{x - 1}

2^{x} - 3 = 0

9 \times 2 7^{x} = 27

e^{x} - e^{- x} = 5

x, y = e^{x \cdot y + 1}