What is the answer to (25^x)/(5^{x+4)}=25^{1-x} ?

The answer to (25^x)/(5^{x+4)}=25^{1-x} is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(25^x)/(5^{x+4)}=25^{1-x}

\frac{2 5 ^{x}}{5 ^{x + 4}} = 2 5^{1 - x}

x = 2

Solution steps

\frac{2 5 ^{x}}{5 ^{x + 4}} = 2 5^{1 - x}

Apply exponent rules

x - 4 = 2 (1 - x)

Solve

x - 4 = 2 (1 - x) : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

3^{2 x + 3} = 3

e^{x^{2} - 1} = 1

8 + e^{1 - 4 x} = 20

e^{x} - 1 - (\frac{6}{e ^{x}}) = 0

e^{x^{2}} = e^{25}

What is the answer to (25^x)/(5^{x+4)}=25^{1-x} ?
The answer to (25^x)/(5^{x+4)}=25^{1-x} is x=2
Solve for x: (25^x)/(5^{x+4)}=25^{1-x}
The solution is x=2