What is the answer to sqrt(8^{x-3)}=\sqrt[3]{4^{2-x}} ?

The answer to sqrt(8^{x-3)}=\sqrt[3]{4^{2-x}} is x= 35/13

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sqrt(8^{x-3)}=\sqrt[3]{4^{2-x}}

x = \frac{35}{13}

Decimal Notation

x = 2.69230 \dots

Solution steps

Apply exponent rules

\frac{3}{2} (x - 3) = \frac{2}{3} (2 - x)

Solve

\frac{3}{2} (x - 3) = \frac{2}{3} (2 - x) : x = \frac{35}{13}

x = \frac{35}{13}

y, x = e^{- y}

2^{x + 4} (2^{x - 4} - 1) = 2^{x} - 16

3 \cdot 4^{x} + 4 \cdot 2^{x} + 8 = 0

3^{x} = x^{4}

x, 0 = 2 e^{- x} x + (- e^{- x}) x^{2}

What is the answer to sqrt(8^{x-3)}=\sqrt[3]{4^{2-x}} ?
The answer to sqrt(8^{x-3)}=\sqrt[3]{4^{2-x}} is x= 35/13
Solve for x: sqrt(8^{x-3)}=\sqrt[3]{4^{2-x}}
The solution is x= 35/13