What is the answer to 6^{x+1}=7^{6x-1} ?

The answer to 6^{x+1}=7^{6x-1} is x=(ln(42))/(6ln(7)-ln(6))

Solve for x: 6^{x+1}=7^{6x-1}

The solution is x=(ln(42))/(6ln(7)-ln(6))

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6^{x + 1} = 7^{6 x - 1}

x = \frac{ln ( 42 )}{6 ln ( 7 ) - ln ( 6 )}

Decimal Notation

x = 0.37816 \dots

Solution steps

6^{x + 1} = 7^{6 x - 1}

Apply exponent rules

(x + 1) ln (6) = (6 x - 1) ln (7)

Solve

(x + 1) ln (6) = (6 x - 1) ln (7) : x = \frac{ln ( 42 )}{6 ln ( 7 ) - ln ( 6 )}

x = \frac{ln ( 42 )}{6 ln ( 7 ) - ln ( 6 )}

- 1 (1 - 2^{x}) = 2094

4^{x} \cdot 3^{2 x} = 6

e^{x^{2}} = e^{7 x - 12}

100 = 65 + 145 e^{- 0.05 \times x}

3 e^{4 x} = 6 e^{7 x}

What is the answer to 6^{x+1}=7^{6x-1} ?
The answer to 6^{x+1}=7^{6x-1} is x=(ln(42))/(6ln(7)-ln(6))
Solve for x: 6^{x+1}=7^{6x-1}
The solution is x=(ln(42))/(6ln(7)-ln(6))