What is the answer to 10^{2x}=2 ?

The answer to 10^{2x}=2 is x=(ln(2))/(2ln(10))

Solve for x: 10^{2x}=2

The solution is x=(ln(2))/(2ln(10))

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1 0^{2 x} = 2

x = \frac{ln ( 2 )}{2 ln ( 10 )}

Decimal Notation

x = 0.15051 \dots

Solution steps

1 0^{2 x} = 2

Apply exponent rules

2 x ln (10) = ln (2)

Solve

2 x ln (10) = ln (2) : x = \frac{ln ( 2 )}{2 ln ( 10 )}

x = \frac{ln ( 2 )}{2 ln ( 10 )}

x \cdot e^{x} = 0

\frac{24 3 ^{x}}{8 1 ^{x + 1}} = 81

2^{x} + 8 \cdot 2^{- x} = 9

2 5^{- x} \cdot 625 = 25

7^{9 x - 2} = 1 0^{3 x + 6}

What is the answer to 10^{2x}=2 ?
The answer to 10^{2x}=2 is x=(ln(2))/(2ln(10))
Solve for x: 10^{2x}=2
The solution is x=(ln(2))/(2ln(10))