What are the solutions to the equation 3x^2+11x-2=0 ?

The solutions to the equation 3x^2+11x-2=0 are x=(-11+sqrt(145))/6 ,x=(-11-sqrt(145))/6

Find the zeros of 3x^2+11x-2=0

The zeros of 3x^2+11x-2=0 are x=(-11+sqrt(145))/6 ,x=(-11-sqrt(145))/6

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3 x^{2} + 11 x - 2 = 0

x = \frac{- 11 + 145}{6}, x = \frac{- 11 - 145}{6}

Decimal Notation

x = 0.17359 \dots, x = - 3.84026 \dots

Solution steps

3 x^{2} + 11 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 (- 2) = 145

x_{1, 2} = \frac{- 11 \pm 145}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 145}{2 \cdot 3}, x_{2} = \frac{- 11 - 145}{2 \cdot 3}

x = \frac{- 11 + 145}{2 \cdot 3} : \frac{- 11 + 145}{6}

x = \frac{- 11 - 145}{2 \cdot 3} : \frac{- 11 - 145}{6}

The solutions to the quadratic equation are:

x = \frac{- 11 + 145}{6}, x = \frac{- 11 - 145}{6}

4 + 3 y = 6 y - 5

\frac{1}{x + 3} + \frac{1}{x + 4} \leq 0

x y - 5 y - 2 x + 10

1300

What are the solutions to the equation 3x^2+11x-2=0 ?
The solutions to the equation 3x^2+11x-2=0 are x=(-11+sqrt(145))/6 ,x=(-11-sqrt(145))/6
Find the zeros of 3x^2+11x-2=0
The zeros of 3x^2+11x-2=0 are x=(-11+sqrt(145))/6 ,x=(-11-sqrt(145))/6