What is the answer to 4^{x+3}\times 8^{2x-1}=sqrt(2) ?

The answer to 4^{x+3}\times 8^{2x-1}=sqrt(2) is x=-5/16

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4^{x+3}\times 8^{2x-1}=sqrt(2)

4^{x + 3} \cdot 8^{2 x - 1} = 2

x = - \frac{5}{16}

Decimal Notation

x = - 0.3125

Solution steps

4^{x + 3} \cdot 8^{2 x - 1} = 2

Apply exponent rules

2 x - 1 + 7 + 3 (2 x - 1) = \frac{1}{2}

Solve

2 x - 1 + 7 + 3 (2 x - 1) = \frac{1}{2} : x = - \frac{5}{16}

x = - \frac{5}{16}

5^{2 x + 1} + 3 \cdot 5^{6 x - 3} = 500

3 e^{3 x + 4} + 8 = e

y, 5^{x + 3} = 2 5^{2 y - 1}

1 = 2^{\frac{1}{x}}

e^{0.4 t} = 8

What is the answer to 4^{x+3}\times 8^{2x-1}=sqrt(2) ?
The answer to 4^{x+3}\times 8^{2x-1}=sqrt(2) is x=-5/16
Solve for x: 4^{x+3}\times 8^{2x-1}=sqrt(2)
The solution is x=-5/16