What is the answer to 3^x-3^{x-2}+3^{x+1}=35 ?

The answer to 3^x-3^{x-2}+3^{x+1}=35 is x=2

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3^x-3^{x-2}+3^{x+1}=35

3^{x} - 3^{x - 2} + 3^{x + 1} = 35

x = 2

Solution steps

3^{x} - 3^{x - 2} + 3^{x + 1} = 35

Factor

3^{x} - 3^{x - 2} + 3^{x + 1} : 35 \cdot 3^{x - 2}

35 \cdot 3^{x - 2} = 35

Divide both sides by

35

3^{x - 2} = 1

Apply exponent rules

(x - 2) ln (3) = ln (1)

Solve

(x - 2) ln (3) = ln (1) : x = 2

x = 2

3^{3 t - 8} = 81

8^{x - 3} = 16

3 = e^{0.055 n}

4^{x - 1} = 8^{1 - x}

e^{\frac{x}{5}} = 84

What is the answer to 3^x-3^{x-2}+3^{x+1}=35 ?
The answer to 3^x-3^{x-2}+3^{x+1}=35 is x=2
Solve for x: 3^x-3^{x-2}+3^{x+1}=35
The solution is x=2