What is the answer to 3^{4x-7}=(3^{2x})/3 ?

The answer to 3^{4x-7}=(3^{2x})/3 is x=3

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3^{4x-7}=(3^{2x})/3

3^{4 x - 7} = \frac{3 ^{2 x}}{3}

x = 3

Solution steps

3^{4 x - 7} = \frac{3 ^{2 x}}{3}

Apply exponent rules

4 x - 7 = 2 x - 1

Solve

4 x - 7 = 2 x - 1 : x = 3

x = 3

y, x = e^{7 y}

6^{x^{2} - 1} = 6^{1 - x^{2}}

k, 0.536585365854 = e^{7 k}

e^{x} = 64

e^{3 x - 2} = 4

What is the answer to 3^{4x-7}=(3^{2x})/3 ?
The answer to 3^{4x-7}=(3^{2x})/3 is x=3
Solve for x: 3^{4x-7}=(3^{2x})/3
The solution is x=3