What is the answer to 7^{3x-1}=49^{x+1} ?

The answer to 7^{3x-1}=49^{x+1} is x=3

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7^{3x-1}=49^{x+1}

7^{3 x - 1} = 4 9^{x + 1}

x = 3

Solution steps

7^{3 x - 1} = 4 9^{x + 1}

Apply exponent rules

3 x - 1 = 2 (x + 1)

Solve

3 x - 1 = 2 (x + 1) : x = 3

x = 3

x, e^{x} = - \frac{1}{2}

81 = 2 7^{x + 2}

9 = 193 \times e^{- x (8)}

128 \times 1 6^{2 x + 1} = 8^{3 - 2 x}

y, x^{x} = y^{y}

What is the answer to 7^{3x-1}=49^{x+1} ?
The answer to 7^{3x-1}=49^{x+1} is x=3
Solve for x: 7^{3x-1}=49^{x+1}
The solution is x=3