What is the answer to 9^x-10\times 3^x+9=0 ?

The answer to 9^x-10\times 3^x+9=0 is x=2,x=0

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9^x-10\times 3^x+9=0

9^{x} - 10 \cdot 3^{x} + 9 = 0

x = 2, x = 0

Solution steps

9^{x} - 10 \cdot 3^{x} + 9 = 0

Apply exponent rules

(3^{x})^{2} - 10 \cdot 3^{x} + 9 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} - 10 u + 9 = 0

Solve

u^{2} - 10 u + 9 = 0 : u = 9, u = 1

u = 9, u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 9 : x = 2

Solve

3^{x} = 1 : x = 0

x = 2, x = 0

5^{a + 2} = \frac{1}{125}

x, y = 1 2^{1 - 0.1 x}

\frac{1 - x}{e ^{x}} = 0

8 1^{1 - 3 x} = 27

What is the answer to 9^x-10\times 3^x+9=0 ?
The answer to 9^x-10\times 3^x+9=0 is x=2,x=0
Solve for x: 9^x-10\times 3^x+9=0
The solution is x=2,x=0