What is the answer to 8^{2x+1}=105 ?

The answer to 8^{2x+1}=105 is x=(ln(105)-3ln(2))/(6ln(2))

Solve for x: 8^{2x+1}=105

The solution is x=(ln(105)-3ln(2))/(6ln(2))

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8^{2 x + 1} = 105

x = \frac{ln ( 105 ) - 3 ln ( 2 )}{6 ln ( 2 )}

Decimal Notation

x = 0.61904 \dots

Solution steps

8^{2 x + 1} = 105

Apply exponent rules

(2 x + 1) ln (8) = ln (105)

Solve

(2 x + 1) ln (8) = ln (105) : x = \frac{ln ( 105 ) - 3 ln ( 2 )}{6 ln ( 2 )}

x = \frac{ln ( 105 ) - 3 ln ( 2 )}{6 ln ( 2 )}

\frac{1 0 ^{3 x}}{1 0 ^{x}} = 30

50 = 400 e^{- 0.0115 t}

x, e^{\frac{x}{2}} = 4 l n x

2^{- b} = 1

5^{5 - x} = \frac{1}{25}

What is the answer to 8^{2x+1}=105 ?
The answer to 8^{2x+1}=105 is x=(ln(105)-3ln(2))/(6ln(2))
Solve for x: 8^{2x+1}=105
The solution is x=(ln(105)-3ln(2))/(6ln(2))