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Popular >

4^x+4^{x-2}=68

Solution

4^{x} + 4^{x - 2} = 68

Solution

x = 3

Solution steps

4^{x} + 4^{x - 2} = 68

Factor

4^{x} + 4^{x - 2} : 17 \cdot 4^{x - 2}

17 \cdot 4^{x - 2} = 68

Divide both sides by

17

4^{x - 2} = 4

Apply exponent rules

x - 2 = 1

Solve

x - 2 = 1 : x = 3

x = 3

Popular Examples

7^{y} = 15

-9=-10+28(19/28)^x

- 9 = - 10 + 28 (\frac{19}{28})^{x}

3^{2x}-3(3^x)=4

3^{2 x} - 3 (3^{x}) = 4

3^{x+1}=9^{x-2}

3^{x + 1} = 9^{x - 2}

A/(1+Be^{t/2)}=C

\frac{A}{1 + B e ^{\frac{t}{2}}} = C

Frequently Asked Questions (FAQ)

What is the answer to 4^x+4^{x-2}=68 ?
The answer to 4^x+4^{x-2}=68 is x=3
Solve for x: 4^x+4^{x-2}=68
The solution is x=3