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Popular >

solvefor n,y^n+4y=0

Solution

solve for

n, y^{n} + 4 y = 0

Solution

n = \frac{ln ( - 4 y )}{ln ( y )}

Solution steps

y^{n} + 4 y = 0

Subtract

4 y

from both sides

y^{n} + 4 y - 4 y = 0 - 4 y

Simplify

y^{n} = - 4 y

Apply exponent rules

n ln (y) = ln (- 4 y)

Solve

n ln (y) = ln (- 4 y) : n = \frac{ln ( - 4 y )}{ln ( y )}

n = \frac{ln ( - 4 y )}{ln ( y )}

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e^{12 - 5 x} - 7 = 123

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64^{x+3}=256^{x+5}

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Frequently Asked Questions (FAQ)

What is the answer to solvefor n,y^n+4y=0 ?
The answer to solvefor n,y^n+4y=0 is n=(ln(-4y))/(ln(y))