What is the answer to 1=10(2^{-t/(30)}) ?

The answer to 1=10(2^{-t/(30)}) is t=(30ln(10))/(ln(2))

Solve for t: 1=10(2^{-t/(30)})

The solution is t=(30ln(10))/(ln(2))

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1 = 10 (2^{- \frac{t}{30}})

t = \frac{30 ln ( 10 )}{ln ( 2 )}

Decimal Notation

t = 99.65784 \dots

Solution steps

1 = 10 (2^{- \frac{t}{30}})

Switch sides

10 \cdot 2^{- \frac{t}{30}} = 1

Divide both sides by

10

2^{- \frac{t}{30}} = \frac{1}{10}

Apply exponent rules

- \frac{t}{30} ln (2) = ln (\frac{1}{10})

Solve

- \frac{t}{30} ln (2) = ln (\frac{1}{10}) : t = \frac{30 ln ( 10 )}{ln ( 2 )}

t = \frac{30 ln ( 10 )}{ln ( 2 )}

e^{x^{2} + 4 x} - 15 = 3

- 4 e^{- 4 x} = 0

- 4 e^{- 4 c} = \frac{e ^{- 12} - 1}{3}

9^{x} - 3^{x + 1} = 54

1 9^{x} = 2

What is the answer to 1=10(2^{-t/(30)}) ?
The answer to 1=10(2^{-t/(30)}) is t=(30ln(10))/(ln(2))
Solve for t: 1=10(2^{-t/(30)})
The solution is t=(30ln(10))/(ln(2))