What is the answer to 5*2^{x+1}=15 ?

The answer to 5*2^{x+1}=15 is x=(ln(3))/(ln(2))-1

Solve for x: 5*2^{x+1}=15

The solution is x=(ln(3))/(ln(2))-1

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5 \cdot 2^{x + 1} = 15

x = \frac{ln ( 3 )}{ln ( 2 )} - 1

Decimal Notation

x = 0.58496 \dots

Solution steps

5 \cdot 2^{x + 1} = 15

Divide both sides by

5

2^{x + 1} = 3

Apply exponent rules

(x + 1) ln (2) = ln (3)

Solve

(x + 1) ln (2) = ln (3) : x = \frac{ln ( 3 )}{ln ( 2 )} - 1

x = \frac{ln ( 3 )}{ln ( 2 )} - 1

3 \times 2^{x} - 2^{x} = 1

e^{x^{2}} + 2 = 4

y, e^{x} y = 1

0 = 5^{x}

8 1^{3 - x} = (\frac{1}{3})^{5 x - 6}

What is the answer to 5*2^{x+1}=15 ?
The answer to 5*2^{x+1}=15 is x=(ln(3))/(ln(2))-1
Solve for x: 5*2^{x+1}=15
The solution is x=(ln(3))/(ln(2))-1