What is the answer to 10=2^{(0.5x)} ?

The answer to 10=2^{(0.5x)} is x=(ln(10))/(0.5ln(2))

Solve for x: 10=2^{(0.5x)}

The solution is x=(ln(10))/(0.5ln(2))

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10 = 2^{(0.5 x)}

x = \frac{ln ( 10 )}{0.5 ln ( 2 )}

Decimal

x = 6.64385 \dots

Solution steps

10 = 2^{(0.5 x)}

Apply exponent rules

ln (10) = 0.5 x ln (2)

Solve

ln (10) = 0.5 x ln (2) : x = \frac{ln ( 10 )}{0.5 ln ( 2 )}

x = \frac{ln ( 10 )}{0.5 ln ( 2 )}

5^{2 x} = 5^{x} + 5

7^{x} = 8^{x - 1}

7^{2 x} + 7^{x} - 6 = 0

7^{2 x} + 7^{x + 1} - 18 = 0

e^{- 2 x} + 6 = 5 e^{- x}

What is the answer to 10=2^{(0.5x)} ?
The answer to 10=2^{(0.5x)} is x=(ln(10))/(0.5ln(2))
Solve for x: 10=2^{(0.5x)}
The solution is x=(ln(10))/(0.5ln(2))