What are the solutions to the equation roots x^3-6x^2+11x-6 ?

The solutions to the equation roots x^3-6x^2+11x-6 are x=1,x=2,x=3

Find the zeros of roots x^3-6x^2+11x-6

The zeros of roots x^3-6x^2+11x-6 are x=1,x=2,x=3

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roots

x^{3} - 6 x^{2} + 11 x - 6

x = 1, x = 2, x = 3

Solution steps

x^{3} - 6 x^{2} + 11 x - 6

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 6 x^{2} + 11 x - 6 = 0

Factor

x^{3} - 6 x^{2} + 11 x - 6 : (x - 1) (x - 2) (x - 3)

(x - 1) (x - 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0 or x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = 1, x = 2, x = 3

y, x = y^{4}

10 x^{9} = 7 x

5 y^{4} - y^{2} + 2 y - 4 = 0

x^{4} - 2 x^{2} + 1

4 x^{3} - 9 x^{2} - 1 = \frac{1}{2}

What are the solutions to the equation roots x^3-6x^2+11x-6 ?
The solutions to the equation roots x^3-6x^2+11x-6 are x=1,x=2,x=3
Find the zeros of roots x^3-6x^2+11x-6
The zeros of roots x^3-6x^2+11x-6 are x=1,x=2,x=3