What are the solutions to the equation roots x^4+12x^3+54x^2+108x+81 ?

The solutions to the equation roots x^4+12x^3+54x^2+108x+81 are x=-3

Find the zeros of roots x^4+12x^3+54x^2+108x+81

The zeros of roots x^4+12x^3+54x^2+108x+81 are x=-3

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roots

x^{4} + 12 x^{3} + 54 x^{2} + 108 x + 81

x = - 3

Solution steps

x^{4} + 12 x^{3} + 54 x^{2} + 108 x + 81

The roots are the intercepts with the x-axis

(y = 0)

x^{4} + 12 x^{3} + 54 x^{2} + 108 x + 81 = 0

Factor

x^{4} + 12 x^{3} + 54 x^{2} + 108 x + 81 : (x + 3)^{4}

(x + 3)^{4} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0

Solve

x + 3 = 0 : x = - 3

The solution is

x = - 3

131946.9 x^{3} - 2968.8 x^{1} - 164.8 = 0

4 x^{4} + 35 x^{2} - 9 = 0

4 x^{3} - 12 x^{2} - 36 x = 0

m^{3} - 5 m^{2} + 3 m + 9 = 0

y, x^{4} + y^{4} = 1

What are the solutions to the equation roots x^4+12x^3+54x^2+108x+81 ?
The solutions to the equation roots x^4+12x^3+54x^2+108x+81 are x=-3
Find the zeros of roots x^4+12x^3+54x^2+108x+81
The zeros of roots x^4+12x^3+54x^2+108x+81 are x=-3