What are the solutions to the equation 5x-17=-x^7 ?

The solutions to the equation 5x-17=-x^7 are x\approx 1.39044…

Find the zeros of 5x-17=-x^7

The zeros of 5x-17=-x^7 are x\approx 1.39044…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x - 17 = - x^{7}

x \approx 1.39044 \dots

Solution steps

5 x - 17 = - x^{7}

Switch sides

- x^{7} = 5 x - 17

Move

17

to the left side

- x^{7} + 17 = 5 x

Move

5 x

to the left side

- x^{7} + 17 - 5 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- x^{7} - 5 x + 17 = 0

Find one solution for

- x^{7} - 5 x + 17 = 0

using Newton-Raphson:

x \approx 1.39044 \dots

Apply long division:

\frac{- x ^{7} - 5 x + 17}{x - 1.39044 \dots} = - x^{6} - 1.39044 \dots x^{5} - 1.93332 \dots x^{4} - 2.68818 \dots x^{3} - 3.73776 \dots x^{2} - 5.19714 \dots x - 12.22632 \dots

- x^{6} - 1.39044 \dots x^{5} - 1.93332 \dots x^{4} - 2.68818 \dots x^{3} - 3.73776 \dots x^{2} - 5.19714 \dots x - 12.22632 \dots \approx 0

Find one solution for

- x^{6} - 1.39044 \dots x^{5} - 1.93332 \dots x^{4} - 2.68818 \dots x^{3} - 3.73776 \dots x^{2} - 5.19714 \dots x - 12.22632 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 1.39044 \dots

x^{3} - 2 x^{2} - 25 x + 50

4 x^{3} + 2 x - 10 = 0

120 x^{2} - 15 x^{4} = 0

- x^{3} + x^{2} - 4 x + 4 = 0

2 x^{4} - 4 x^{3} = - 2 x^{2}

What are the solutions to the equation 5x-17=-x^7 ?
The solutions to the equation 5x-17=-x^7 are x\approx 1.39044…
Find the zeros of 5x-17=-x^7
The zeros of 5x-17=-x^7 are x\approx 1.39044…