What are the solutions to the equation 3x^3+4x^2+4x+9=9 ?

The solutions to the equation 3x^3+4x^2+4x+9=9 are x=0,x=-2/3+i(2sqrt(2))/3 ,x=-2/3-i(2sqrt(2))/3

Find the zeros of 3x^3+4x^2+4x+9=9

The zeros of 3x^3+4x^2+4x+9=9 are x=0,x=-2/3+i(2sqrt(2))/3 ,x=-2/3-i(2sqrt(2))/3

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3 x^{3} + 4 x^{2} + 4 x + 9 = 9

x = 0, x = - \frac{2}{3} + i \frac{2 2}{3}, x = - \frac{2}{3} - i \frac{2 2}{3}

Solution steps

3 x^{3} + 4 x^{2} + 4 x + 9 = 9

Move

9

to the right side

3 x^{3} + 4 x^{2} + 4 x = 0

Factor

3 x^{3} + 4 x^{2} + 4 x : x (3 x^{2} + 4 x + 4)

x (3 x^{2} + 4 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x^{2} + 4 x + 4 = 0

Solve

3 x^{2} + 4 x + 4 = 0 : x = - \frac{2}{3} + i \frac{2 2}{3}, x = - \frac{2}{3} - i \frac{2 2}{3}

The solutions are

x = 0, x = - \frac{2}{3} + i \frac{2 2}{3}, x = - \frac{2}{3} - i \frac{2 2}{3}

x^{5} = 5 x^{3}

6 y^{5} - 8 y^{3} - 2 y + 1 = 0

(x^{2} + 3)^{3} = 0

x^{5} - 10 x^{3} + 36 x = 0

12 x^{3} + 12 x^{2} + 6 = 0

What are the solutions to the equation 3x^3+4x^2+4x+9=9 ?
The solutions to the equation 3x^3+4x^2+4x+9=9 are x=0,x=-2/3+i(2sqrt(2))/3 ,x=-2/3-i(2sqrt(2))/3
Find the zeros of 3x^3+4x^2+4x+9=9
The zeros of 3x^3+4x^2+4x+9=9 are x=0,x=-2/3+i(2sqrt(2))/3 ,x=-2/3-i(2sqrt(2))/3