What are the solutions to the equation roots x^3-3x+2 ?

The solutions to the equation roots x^3-3x+2 are x=1,x=-2

Find the zeros of roots x^3-3x+2

The zeros of roots x^3-3x+2 are x=1,x=-2

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roots

x^{3} - 3 x + 2

x = 1, x = - 2

Solution steps

x^{3} - 3 x + 2

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 3 x + 2 = 0

Factor

x^{3} - 3 x + 2 : (x - 1)^{2} (x + 2)

(x - 1)^{2} (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 1, x = - 2

4 x^{3} - 12 x^{2} - 11 x - 2 = 0

x^{5} = 64 x^{2}

- 16 x - 4 x^{3} = 164

20 x^{3} + 60 x^{2} = 0

x^{23} x + 2 = 0

What are the solutions to the equation roots x^3-3x+2 ?
The solutions to the equation roots x^3-3x+2 are x=1,x=-2
Find the zeros of roots x^3-3x+2
The zeros of roots x^3-3x+2 are x=1,x=-2