What are the solutions to the equation 120x^3+12x^2=0 ?

The solutions to the equation 120x^3+12x^2=0 are x=0,x=-1/10

Find the zeros of 120x^3+12x^2=0

The zeros of 120x^3+12x^2=0 are x=0,x=-1/10

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120 x^{3} + 12 x^{2} = 0

x = 0, x = - \frac{1}{10}

Decimal Notation

x = 0, x = - 0.1

Solution steps

120 x^{3} + 12 x^{2} = 0

Factor

120 x^{3} + 12 x^{2} : 12 x^{2} (10 x + 1)

12 x^{2} (10 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 10 x + 1 = 0

Solve

10 x + 1 = 0 : x = - \frac{1}{10}

The solutions are

x = 0, x = - \frac{1}{10}

x^{4} - 7 x^{2} + 6 x = 0

x^{9} = 1

x^{4} + x^{3} - 10 x^{2} + x + 1 = 0

x^{3} + 7 = 5

11 x^{3} + 15 x^{2} - 25 x + 7 = 0

What are the solutions to the equation 120x^3+12x^2=0 ?
The solutions to the equation 120x^3+12x^2=0 are x=0,x=-1/10
Find the zeros of 120x^3+12x^2=0
The zeros of 120x^3+12x^2=0 are x=0,x=-1/10