What are the solutions to the equation 15x-10=6x-(x^2)(-x^3) ?

The solutions to the equation 15x-10=6x-(x^2)(-x^3) are x\approx-1.93968…

Find the zeros of 15x-10=6x-(x^2)(-x^3)

The zeros of 15x-10=6x-(x^2)(-x^3) are x\approx-1.93968…

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15 x - 10 = 6 x - (x^{2}) (- x^{3})

x \approx - 1.93968 \dots

Solution steps

15 x - 10 = 6 x - (x^{2}) (- x^{3})

Refine

15 x - 10 = 6 x + x^{5}

Switch sides

6 x + x^{5} = 15 x - 10

Move

10

to the left side

6 x + x^{5} + 10 = 15 x

Move

15 x

to the left side

x^{5} - 9 x + 10 = 0

Find one solution for

x^{5} - 9 x + 10 = 0

using Newton-Raphson:

x \approx - 1.93968 \dots

Apply long division:

\frac{x ^{5} - 9 x + 10}{x + 1.93968 \dots} = x^{4} - 1.93968 \dots x^{3} + 3.76237 \dots x^{2} - 7.29782 \dots x + 5.15547 \dots

x^{4} - 1.93968 \dots x^{3} + 3.76237 \dots x^{2} - 7.29782 \dots x + 5.15547 \dots \approx 0

Find one solution for

x^{4} - 1.93968 \dots x^{3} + 3.76237 \dots x^{2} - 7.29782 \dots x + 5.15547 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 1.93968 \dots

x^{5} - 5 x + 1 = 0

x^{3} = 1 - i

y, 9 y^{2} = 4 x^{3}

2 x^{4} - 48 x^{2} = 0

x^{2} - x^{3} = 12

What are the solutions to the equation 15x-10=6x-(x^2)(-x^3) ?
The solutions to the equation 15x-10=6x-(x^2)(-x^3) are x\approx-1.93968…
Find the zeros of 15x-10=6x-(x^2)(-x^3)
The zeros of 15x-10=6x-(x^2)(-x^3) are x\approx-1.93968…