What are the solutions to the equation 6=1-2n^5 ?

The solutions to the equation 6=1-2n^5 are n=-\sqrt[5]{5/2}

Find the zeros of 6=1-2n^5

The zeros of 6=1-2n^5 are n=-\sqrt[5]{5/2}

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6 = 1 - 2 n^{5}

Decimal Notation

n = - 1.20112 \dots

Solution steps

6 = 1 - 2 n^{5}

Switch sides

1 - 2 n^{5} = 6

Move

1

to the right side

- 2 n^{5} = 5

Divide both sides by

- 2

n^{5} = - \frac{5}{2}

For

x^{n} = f (a)

, n is odd, the solution is

x^{4} = (3 x - 70)^{2}

m^{3} - 2 m^{2} - m + 2 = 0

x^{3} = - x^{2}

1 + 2 x - 3 x^{2} + x^{3} = 2 x - 3

x^{3} - 3 x^{2} + 3 x - 1 = 0

What are the solutions to the equation 6=1-2n^5 ?
The solutions to the equation 6=1-2n^5 are n=-\sqrt[5]{5/2}
Find the zeros of 6=1-2n^5
The zeros of 6=1-2n^5 are n=-\sqrt[5]{5/2}