What are the solutions to the equation factor x^3-4x^2-4x+16=0 ?

The solutions to the equation factor x^3-4x^2-4x+16=0 are x=4,x=-2,x=2

Find the zeros of factor x^3-4x^2-4x+16=0

The zeros of factor x^3-4x^2-4x+16=0 are x=4,x=-2,x=2

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factor

x^{3} - 4 x^{2} - 4 x + 16 = 0

x = 4, x = - 2, x = 2

Solution steps

x^{3} - 4 x^{2} - 4 x + 16 = 0

Factor

x^{3} - 4 x^{2} - 4 x + 16 : (x - 4) (x + 2) (x - 2)

(x - 4) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 4, x = - 2, x = 2

(x^{2} - 64)^{2} + (x^{2} + 5 x - 104)^{2} = 0

5 x^{3} - 7 x + 2

x^{5} - 2 x^{4} + 2 x^{3} - 4 x^{2} - 2 = 0

x^{4} + 2 x^{2} + 1

4 x^{4} - 2 x^{2} + 1 = 0

What are the solutions to the equation factor x^3-4x^2-4x+16=0 ?
The solutions to the equation factor x^3-4x^2-4x+16=0 are x=4,x=-2,x=2
Find the zeros of factor x^3-4x^2-4x+16=0
The zeros of factor x^3-4x^2-4x+16=0 are x=4,x=-2,x=2