What are the solutions to the equation x^4-2x^3-5x^2+8x+4=0 ?

The solutions to the equation x^4-2x^3-5x^2+8x+4=0 are x=-2,x=2,x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of x^4-2x^3-5x^2+8x+4=0

The zeros of x^4-2x^3-5x^2+8x+4=0 are x=-2,x=2,x=1+sqrt(2),x=1-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} - 2 x^{3} - 5 x^{2} + 8 x + 4 = 0

x = - 2, x = 2, x = 1 + 2, x = 1 - 2

Decimal Notation

x = - 2, x = 2, x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

x^{4} - 2 x^{3} - 5 x^{2} + 8 x + 4 = 0

Factor

x^{4} - 2 x^{3} - 5 x^{2} + 8 x + 4 : (x + 2) (x - 2) (x^{2} - 2 x - 1)

(x + 2) (x - 2) (x^{2} - 2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 2 = 0 or x^{2} - 2 x - 1 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

Solve

x^{2} - 2 x - 1 = 0 : x = 1 + 2, x = 1 - 2

The solutions are

x = - 2, x = 2, x = 1 + 2, x = 1 - 2

3 x^{3} + 81 = 0

16 x^{3} = 54

x^{3} + x^{2} - 2

n^{6} - n^{3} = 2

x^{3} + 10.6 x^{2} + 7 x + 10

What are the solutions to the equation x^4-2x^3-5x^2+8x+4=0 ?
The solutions to the equation x^4-2x^3-5x^2+8x+4=0 are x=-2,x=2,x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of x^4-2x^3-5x^2+8x+4=0
The zeros of x^4-2x^3-5x^2+8x+4=0 are x=-2,x=2,x=1+sqrt(2),x=1-sqrt(2)