What are the solutions to the equation 2x^3-3x^2+18x-27=0 ?

The solutions to the equation 2x^3-3x^2+18x-27=0 are x= 3/2 ,x=3i,x=-3i

Find the zeros of 2x^3-3x^2+18x-27=0

The zeros of 2x^3-3x^2+18x-27=0 are x= 3/2 ,x=3i,x=-3i

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2 x^{3} - 3 x^{2} + 18 x - 27 = 0

x = \frac{3}{2}, x = 3 i, x = - 3 i

Solution steps

2 x^{3} - 3 x^{2} + 18 x - 27 = 0

Factor

2 x^{3} - 3 x^{2} + 18 x - 27 : (2 x - 3) (x^{2} + 9)

(2 x - 3) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or x^{2} + 9 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = \frac{3}{2}, x = 3 i, x = - 3 i

x^{2} x + 5 a = 30

0.3 x^{9} - 2.4 = 0

4 x^{3} - 21 x^{2} = 0

x^{7} - 16 x^{4} + 64 x = 0

2 x^{3} - 3 x^{2} - x + 1 = 0

What are the solutions to the equation 2x^3-3x^2+18x-27=0 ?
The solutions to the equation 2x^3-3x^2+18x-27=0 are x= 3/2 ,x=3i,x=-3i
Find the zeros of 2x^3-3x^2+18x-27=0
The zeros of 2x^3-3x^2+18x-27=0 are x= 3/2 ,x=3i,x=-3i