What are the solutions to the equation x^5+2x^3+x=0 ?

The solutions to the equation x^5+2x^3+x=0 are x=0,x=i,x=-i

Find the zeros of x^5+2x^3+x=0

The zeros of x^5+2x^3+x=0 are x=0,x=i,x=-i

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x^{5} + 2 x^{3} + x = 0

x = 0, x = i, x = - i

Solution steps

x^{5} + 2 x^{3} + x = 0

Factor

x^{5} + 2 x^{3} + x : x (x^{2} + 1)^{2}

x (x^{2} + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 1 = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = 0, x = i, x = - i

x^{3} + 7 x^{2} - 9 x - 63 = 0

125 t^{10} - 2 t^{7} = 0

x^{4} = (4 x - 5)^{2}

- 3 (2 x + 1)^{3} = - 192

(x^{2} - x + 1)^{2} = 0

What are the solutions to the equation x^5+2x^3+x=0 ?
The solutions to the equation x^5+2x^3+x=0 are x=0,x=i,x=-i
Find the zeros of x^5+2x^3+x=0
The zeros of x^5+2x^3+x=0 are x=0,x=i,x=-i