What are the solutions to the equation roots x^3-4x^2+x+6 ?

The solutions to the equation roots x^3-4x^2+x+6 are x=-1,x=2,x=3

Find the zeros of roots x^3-4x^2+x+6

The zeros of roots x^3-4x^2+x+6 are x=-1,x=2,x=3

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roots

x^{3} - 4 x^{2} + x + 6

x = - 1, x = 2, x = 3

Solution steps

x^{3} - 4 x^{2} + x + 6

The roots are the intercepts with the x-axis

(y = 0)

x^{3} - 4 x^{2} + x + 6 = 0

Factor

x^{3} - 4 x^{2} + x + 6 : (x + 1) (x - 2) (x - 3)

(x + 1) (x - 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = 2, x = 3

m^{3} - 6 m^{2} = 0

x^{3} - 9 x^{2} + 24 x - 20 = 0

x^{4} - x^{3} - 3 x^{2} + 4 x - 4 = 0

x^{3} + 6 x^{2} - 7 x - 60 = 0

x^{6} + x^{3} + 1 = 0

What are the solutions to the equation roots x^3-4x^2+x+6 ?
The solutions to the equation roots x^3-4x^2+x+6 are x=-1,x=2,x=3
Find the zeros of roots x^3-4x^2+x+6
The zeros of roots x^3-4x^2+x+6 are x=-1,x=2,x=3