What are the solutions to the equation 3x^4+10x^2-8=0 ?

The solutions to the equation 3x^4+10x^2-8=0 are x=sqrt(2/3),x=-sqrt(2/3),x=2i,x=-2i

Find the zeros of 3x^4+10x^2-8=0

The zeros of 3x^4+10x^2-8=0 are x=sqrt(2/3),x=-sqrt(2/3),x=2i,x=-2i

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3 x^{4} + 10 x^{2} - 8 = 0

x = \frac{2}{3}, x = - \frac{2}{3}, x = 2 i, x = - 2 i

Solution steps

3 x^{4} + 10 x^{2} - 8 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

3 u^{2} + 10 u - 8 = 0

Solve

3 u^{2} + 10 u - 8 = 0 : u = \frac{2}{3}, u = - 4

u = \frac{2}{3}, u = - 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{2}{3} : x = \frac{2}{3}, x = - \frac{2}{3}

Solve

x^{2} = - 4 : x = 2 i, x = - 2 i

The solutions are

x = \frac{2}{3}, x = - \frac{2}{3}, x = 2 i, x = - 2 i

2 x^{4} - 30 x^{2} - 2 x = 0

x^{3} - 3 x^{2} - 4 x + 12

0 = x^{3} - 3 x^{2} + 3

4 x^{4} = 24 x^{2} + 108

z^{3} - 0.9887 z^{2} + 0.08362 z - 0.001075 = 0

What are the solutions to the equation 3x^4+10x^2-8=0 ?
The solutions to the equation 3x^4+10x^2-8=0 are x=sqrt(2/3),x=-sqrt(2/3),x=2i,x=-2i
Find the zeros of 3x^4+10x^2-8=0
The zeros of 3x^4+10x^2-8=0 are x=sqrt(2/3),x=-sqrt(2/3),x=2i,x=-2i