What are the solutions to the equation 26=16*(1+x)^4 ?

The solutions to the equation 26=16*(1+x)^4 are x=\sqrt[4]{13/8}-1,x=-\sqrt[4]{13/8}-1

Find the zeros of 26=16*(1+x)^4

The zeros of 26=16*(1+x)^4 are x=\sqrt[4]{13/8}-1,x=-\sqrt[4]{13/8}-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

26 = 16 \cdot (1 + x)^{4}

x = 4 \frac{13}{8} - 1, x = - 4 \frac{13}{8} - 1

Decimal

x = 0.12905 \dots, x = - 2.12905 \dots

Solution steps

26 = 16 (1 + x)^{4}

Switch sides

16 (1 + x)^{4} = 26

Divide both sides by

16

(1 + x)^{4} = \frac{13}{8}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

g (x) = n f (a), - n f (a)

Solve

1 + x = 4 \frac{13}{8} : x = 4 \frac{13}{8} - 1

Solve

1 + x = - 4 \frac{13}{8} : x = - 4 \frac{13}{8} - 1

The solutions are

x = 4 \frac{13}{8} - 1, x = - 4 \frac{13}{8} - 1

x^{6} - 2 x^{3} + 2

4 x^{3} + 6 x^{2} - 8 x + 1 = 0

x^{4} + x^{3} - 3 x^{2} - 5 x - 2 = 0

m^{4} - 625 = 0

8 x^{5} + 5 x^{2} = 4 x^{2}

What are the solutions to the equation 26=16*(1+x)^4 ?
The solutions to the equation 26=16*(1+x)^4 are x=\sqrt[4]{13/8}-1,x=-\sqrt[4]{13/8}-1
Find the zeros of 26=16*(1+x)^4
The zeros of 26=16*(1+x)^4 are x=\sqrt[4]{13/8}-1,x=-\sqrt[4]{13/8}-1