What are the solutions to the equation (5x+3)^2=19 ?

The solutions to the equation (5x+3)^2=19 are x=(sqrt(19)-3)/5 ,x=(-sqrt(19)-3)/5

Find the zeros of (5x+3)^2=19

The zeros of (5x+3)^2=19 are x=(sqrt(19)-3)/5 ,x=(-sqrt(19)-3)/5

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(5 x + 3)^{2} = 19

x = \frac{19 - 3}{5}, x = \frac{- 19 - 3}{5}

Decimal Notation

x = 0.27177 \dots, x = - 1.47177 \dots

Solution steps

(5 x + 3)^{2} = 19

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 3 = 19 : x = \frac{19 - 3}{5}

Solve

5 x + 3 = - 19 : x = \frac{- 19 - 3}{5}

The solutions to the quadratic equation are:

x = \frac{19 - 3}{5}, x = \frac{- 19 - 3}{5}

\frac{x y ^{6}}{x y ^{8}}

- 2 x + 1 = 7

lo g_{10} (5) = x

\frac{5}{12} + \frac{7}{4} - 1

3 x^{6} - 75 x^{4} - 48 x^{2} + 1200

What are the solutions to the equation (5x+3)^2=19 ?
The solutions to the equation (5x+3)^2=19 are x=(sqrt(19)-3)/5 ,x=(-sqrt(19)-3)/5
Find the zeros of (5x+3)^2=19
The zeros of (5x+3)^2=19 are x=(sqrt(19)-3)/5 ,x=(-sqrt(19)-3)/5