What are the solutions to the equation roots x^4-5x^2+4 ?

The solutions to the equation roots x^4-5x^2+4 are x=2,x=-2,x=1,x=-1

Find the zeros of roots x^4-5x^2+4

The zeros of roots x^4-5x^2+4 are x=2,x=-2,x=1,x=-1

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roots

x^{4} - 5 x^{2} + 4

x = 2, x = - 2, x = 1, x = - 1

Solution steps

x^{4} - 5 x^{2} + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{4} - 5 x^{2} + 4 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 5 u + 4 = 0

Solve

u^{2} - 5 u + 4 = 0 : u = 4, u = 1

u = 4, u = 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 4 : x = 2, x = - 2

Solve

x^{2} = 1 : x = 1, x = - 1

The solutions are

x = 2, x = - 2, x = 1, x = - 1

x^{4} - 2 x^{3} + 6 x^{2} - 18 x - 27 = 0

r^{3} + r^{2} - r - 1 = 0

x^{4} - x^{2} + \frac{1}{4} = 0

x^{3} - 12 x + 11 = 0

7 x^{3} - x^{2} - 7 x + 1

What are the solutions to the equation roots x^4-5x^2+4 ?
The solutions to the equation roots x^4-5x^2+4 are x=2,x=-2,x=1,x=-1
Find the zeros of roots x^4-5x^2+4
The zeros of roots x^4-5x^2+4 are x=2,x=-2,x=1,x=-1