What are the solutions to the equation x^3-5x^2-25x+125=0 ?

The solutions to the equation x^3-5x^2-25x+125=0 are x=5,x=-5

Find the zeros of x^3-5x^2-25x+125=0

The zeros of x^3-5x^2-25x+125=0 are x=5,x=-5

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x^{3} - 5 x^{2} - 25 x + 125 = 0

x = 5, x = - 5

Solution steps

x^{3} - 5 x^{2} - 25 x + 125 = 0

Factor

x^{3} - 5 x^{2} - 25 x + 125 : (x - 5)^{2} (x + 5)

(x - 5)^{2} (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 5 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 5 = 0 : x = - 5

The solutions are

x = 5, x = - 5

x^{3} = (- 1 - 3 i)

7 \times x - 9 = 4 \times x^{27}

t^{4} - 3 t^{3} - 40 t^{2} = 0

y, 2 x^{3} - 3 y^{2} = 8

x^{8} - 2 x^{4} + 4 = 0

What are the solutions to the equation x^3-5x^2-25x+125=0 ?
The solutions to the equation x^3-5x^2-25x+125=0 are x=5,x=-5
Find the zeros of x^3-5x^2-25x+125=0
The zeros of x^3-5x^2-25x+125=0 are x=5,x=-5