What are the solutions to the equation 4x^3+3x^2+2x=0 ?

The solutions to the equation 4x^3+3x^2+2x=0 are x=0,x=-3/8+i(sqrt(23))/8 ,x=-3/8-i(sqrt(23))/8

Find the zeros of 4x^3+3x^2+2x=0

The zeros of 4x^3+3x^2+2x=0 are x=0,x=-3/8+i(sqrt(23))/8 ,x=-3/8-i(sqrt(23))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{3} + 3 x^{2} + 2 x = 0

x = 0, x = - \frac{3}{8} + i \frac{23}{8}, x = - \frac{3}{8} - i \frac{23}{8}

Solution steps

4 x^{3} + 3 x^{2} + 2 x = 0

Factor

4 x^{3} + 3 x^{2} + 2 x : x (4 x^{2} + 3 x + 2)

x (4 x^{2} + 3 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x^{2} + 3 x + 2 = 0

Solve

4 x^{2} + 3 x + 2 = 0 : x = - \frac{3}{8} + i \frac{23}{8}, x = - \frac{3}{8} - i \frac{23}{8}

The solutions are

x = 0, x = - \frac{3}{8} + i \frac{23}{8}, x = - \frac{3}{8} - i \frac{23}{8}

6 x^{32} = 3 x^{96}

2 x^{2} - 4 x^{5} = 0

6 x^{3} + 5 x^{2} - 4 x + 4 = 0

n^{3} - n = 5 n^{2} - 5

x^{3} - 8 = 0

What are the solutions to the equation 4x^3+3x^2+2x=0 ?
The solutions to the equation 4x^3+3x^2+2x=0 are x=0,x=-3/8+i(sqrt(23))/8 ,x=-3/8-i(sqrt(23))/8
Find the zeros of 4x^3+3x^2+2x=0
The zeros of 4x^3+3x^2+2x=0 are x=0,x=-3/8+i(sqrt(23))/8 ,x=-3/8-i(sqrt(23))/8