What are the solutions to the equation roots x^3+8x^2+37x+50 ?

The solutions to the equation roots x^3+8x^2+37x+50 are x=-2,x=-3+4i,x=-3-4i

Find the zeros of roots x^3+8x^2+37x+50

The zeros of roots x^3+8x^2+37x+50 are x=-2,x=-3+4i,x=-3-4i

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roots

x^{3} + 8 x^{2} + 37 x + 50

x = - 2, x = - 3 + 4 i, x = - 3 - 4 i

Solution steps

x^{3} + 8 x^{2} + 37 x + 50

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 8 x^{2} + 37 x + 50 = 0

Factor

x^{3} + 8 x^{2} + 37 x + 50 : (x + 2) (x^{2} + 6 x + 25)

(x + 2) (x^{2} + 6 x + 25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 6 x + 25 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 6 x + 25 = 0 : x = - 3 + 4 i, x = - 3 - 4 i

The solutions are

x = - 2, x = - 3 + 4 i, x = - 3 - 4 i

(x - 4)^{4} = x^{4}

2.5 x^{4} + 3 x^{3} - 2.6 x^{2} - 5.1 x - 5.6 = 0

2 x^{4} - 2 x^{3} - 2 x^{2} + 2 x = 0

x^{6} - 2 = 0

x^{3} - 11 x^{2} + 43 x - 65

What are the solutions to the equation roots x^3+8x^2+37x+50 ?
The solutions to the equation roots x^3+8x^2+37x+50 are x=-2,x=-3+4i,x=-3-4i
Find the zeros of roots x^3+8x^2+37x+50
The zeros of roots x^3+8x^2+37x+50 are x=-2,x=-3+4i,x=-3-4i