What are the solutions to the equation -1x^3+11x^2-32x+28=0 ?

The solutions to the equation -1x^3+11x^2-32x+28=0 are x=2,x=7

Find the zeros of -1x^3+11x^2-32x+28=0

The zeros of -1x^3+11x^2-32x+28=0 are x=2,x=7

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- 1 x^{3} + 11 x^{2} - 32 x + 28 = 0

x = 2, x = 7

Solution steps

- 1 \cdot x^{3} + 11 x^{2} - 32 x + 28 = 0

Refine

- x^{3} + 11 x^{2} - 32 x + 28 = 0

Factor

- x^{3} + 11 x^{2} - 32 x + 28 : - (x - 2)^{2} (x - 7)

- (x - 2)^{2} (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 7 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 7 = 0 : x = 7

The solutions are

x = 2, x = 7

x^{3} - 8 x^{2} + 22 x - 20 = 0

x^{3} + 6 x^{2} + 11 x + 6

x^{3} + 5 x^{2} - 8 x - 48 = 0

x^{3} - 8 x^{2} + 4 x + 48 = 0

x^{3} - 34 x - 12 = 0

What are the solutions to the equation -1x^3+11x^2-32x+28=0 ?
The solutions to the equation -1x^3+11x^2-32x+28=0 are x=2,x=7
Find the zeros of -1x^3+11x^2-32x+28=0
The zeros of -1x^3+11x^2-32x+28=0 are x=2,x=7