What are the solutions to the equation 243x^5+32=100000 ?

The solutions to the equation 243x^5+32=100000 are x=(2\sqrt[5]{3124})/3

Find the zeros of 243x^5+32=100000

The zeros of 243x^5+32=100000 are x=(2\sqrt[5]{3124})/3

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243 x^{5} + 32 = 100000

Decimal Notation

x = 3.33311 \dots

Solution steps

243 x^{5} + 32 = 100000

Move

32

to the right side

243 x^{5} = 99968

Divide both sides by

243

x^{5} = \frac{99968}{243}

For

x^{n} = f (a)

, n is odd, the solution is

6 x^{4} - 5 x^{3} + 7 x^{2} - 5 x + 1 = 0

x^{3} + 5 x^{2} + 10 x + 50 = 0

30 x - 60 x^{3} = 0

x^{4} + 2 x^{2} + 2 = 0

2 - 3 x + x^{3} = 0

What are the solutions to the equation 243x^5+32=100000 ?
The solutions to the equation 243x^5+32=100000 are x=(2\sqrt[5]{3124})/3
Find the zeros of 243x^5+32=100000
The zeros of 243x^5+32=100000 are x=(2\sqrt[5]{3124})/3