What are the solutions to the equation 6x^3+37x^2-34x+7=0 ?

The solutions to the equation 6x^3+37x^2-34x+7=0 are x=-7,x= 1/3 ,x= 1/2

Find the zeros of 6x^3+37x^2-34x+7=0

The zeros of 6x^3+37x^2-34x+7=0 are x=-7,x= 1/3 ,x= 1/2

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6 x^{3} + 37 x^{2} - 34 x + 7 = 0

x = - 7, x = \frac{1}{3}, x = \frac{1}{2}

Decimal Notation

x = - 7, x = 0.33333 \dots, x = 0.5

Solution steps

6 x^{3} + 37 x^{2} - 34 x + 7 = 0

Factor

6 x^{3} + 37 x^{2} - 34 x + 7 : (x + 7) (3 x - 1) (2 x - 1)

(x + 7) (3 x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0 or 3 x - 1 = 0 or 2 x - 1 = 0

Solve

x + 7 = 0 : x = - 7

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = - 7, x = \frac{1}{3}, x = \frac{1}{2}

x^{3} = x^{2} - 7 x + 7

n^{3} + 2 n^{2} - 9 n - 18 = 0

z^{5} = 1 + i

x^{3} - 2 x^{2} + 5 x - 1 = 2

x^{4} + 8 x^{3} + 14 x^{2} - 17 x - 42 = 0

What are the solutions to the equation 6x^3+37x^2-34x+7=0 ?
The solutions to the equation 6x^3+37x^2-34x+7=0 are x=-7,x= 1/3 ,x= 1/2
Find the zeros of 6x^3+37x^2-34x+7=0
The zeros of 6x^3+37x^2-34x+7=0 are x=-7,x= 1/3 ,x= 1/2