What are the solutions to the equation roots 2x^3+5x^2-6x-9 ?

The solutions to the equation roots 2x^3+5x^2-6x-9 are x=-1,x= 3/2 ,x=-3

Find the zeros of roots 2x^3+5x^2-6x-9

The zeros of roots 2x^3+5x^2-6x-9 are x=-1,x= 3/2 ,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

2 x^{3} + 5 x^{2} - 6 x - 9

x = - 1, x = \frac{3}{2}, x = - 3

Solution steps

2 x^{3} + 5 x^{2} - 6 x - 9

The roots are the intercepts with the x-axis

(y = 0)

2 x^{3} + 5 x^{2} - 6 x - 9 = 0

Factor

2 x^{3} + 5 x^{2} - 6 x - 9 : (x + 1) (2 x - 3) (x + 3)

(x + 1) (2 x - 3) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 2 x - 3 = 0 or x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x + 3 = 0 : x = - 3

The solutions are

x = - 1, x = \frac{3}{2}, x = - 3

x^{3} + 3 x^{2} + x + 1 = 0

a, a^{4} = \frac{4}{3} a^{2} b + \frac{4}{9} b^{2}

y, x^{4} y - 20 = 0

2 x^{3} + 5 x^{2} - 13 x + 7 = 0

(x - 3)^{4} - 3 (x - 3)^{2} - 10 = 0

What are the solutions to the equation roots 2x^3+5x^2-6x-9 ?
The solutions to the equation roots 2x^3+5x^2-6x-9 are x=-1,x= 3/2 ,x=-3
Find the zeros of roots 2x^3+5x^2-6x-9
The zeros of roots 2x^3+5x^2-6x-9 are x=-1,x= 3/2 ,x=-3