What are the solutions to the equation 4x^3+5x^2-16x-20=0 ?

The solutions to the equation 4x^3+5x^2-16x-20=0 are x=-5/4 ,x=-2,x=2

Find the zeros of 4x^3+5x^2-16x-20=0

The zeros of 4x^3+5x^2-16x-20=0 are x=-5/4 ,x=-2,x=2

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4 x^{3} + 5 x^{2} - 16 x - 20 = 0

x = - \frac{5}{4}, x = - 2, x = 2

Decimal Notation

x = - 1.25, x = - 2, x = 2

Solution steps

4 x^{3} + 5 x^{2} - 16 x - 20 = 0

Factor

4 x^{3} + 5 x^{2} - 16 x - 20 : (4 x + 5) (x + 2) (x - 2)

(4 x + 5) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 5 = 0 or x + 2 = 0 or x - 2 = 0

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{5}{4}, x = - 2, x = 2

x^{3} + 6 x^{2} - 9 x - 54 = 0

1 + x^{8}

(x^{2} - x + 1) (x^{2} - x - 2) = 378

x^{3} + 81 = 0

r^{3} - 7 r - 6 = 0

What are the solutions to the equation 4x^3+5x^2-16x-20=0 ?
The solutions to the equation 4x^3+5x^2-16x-20=0 are x=-5/4 ,x=-2,x=2
Find the zeros of 4x^3+5x^2-16x-20=0
The zeros of 4x^3+5x^2-16x-20=0 are x=-5/4 ,x=-2,x=2